Question

1.what is the value of K if the line 3x-2y=1 is perpendicular to the line y-(2K+1)x=3?

Answer 1

product of slopes of perpendicular lines = -1

Answer 2

yup

Answer 3

So where are you stuck ?

Answer 4

uhm.. EVERYTHING??? ahahaha.xD

Answer 5

Can you tell me the slope of the line 3x-2y = 1 ?

Answer 6

Hint : try to compare with y= mx+c form, where m is the slope

Answer 7

wait,,

Answer 8

negative 1/y???

Answer 9

m should be a constant. try again.

Answer 10

,, aw, my brain hurts,

Answer 11

Sure it does. hmm

Answer 12

Leme guide you through 1st line, you try on your own for second.

Answer 13

okaaay, thanks,

Answer 14

3x - 2y =1
3x = 2y+1
(3/2)x = y + (1/2)
y = (3/2)x - (1/2)
Did you follow ?

Answer 15

y-(2K+1)x=3
adding (2K+1)x to both sides we get
y = (2K+1)x +3

Answer 16

so the slope is -3

Answer 17

from where did you pick -3 ?

Answer 18

y = 3/2x-1/2
what is the slope now??

Answer 19

oh.xD hahaha the slope is 3/2

Answer 20

yes exactly

Answer 21

y = (2K+1)x +3
and the here the slope is ??

Answer 22

reply.

Answer 23

waiiit,,xD

Answer 24

2k??/

Answer 25

no

Answer 26

try it again

Answer 27

waiit,, isnt the slope for the 1st eqAuation 3??

Answer 28

-2y=-3x+1
(-2y=-3x+1)-1
2y=3x-1
so slope is 3

Answer 29

oh, you're gonna divide it by 2

Answer 30

yes

Answer 31

the second equation is sooo confusing.

Answer 32

y = (2K+1)x +3
and the here the slope is ??

formula is y=mx+b

here m = slope and b = y-intercept

Answer 33

(2K+1)????

Answer 34

yes exactly

Answer 35

i thought, you were, going to multiply it from the x . hahaha

Answer 36

then how to get the value of k??

Answer 37

m1m2=-1

now these line are perpendicular to each other
thus their slopes are related as
m1 = -1/m2
here m1 = 3/2 and m2 = 2k+1

3/2 = -1/(2k+1)
can you solve for K now???

Answer 38

-5/6???

Answer 39

sorry it correct so
K = -5/6
is the required value of K

Answer 40

okay,,xD

Answer 41

.oh,, so i'm finished,, thaaaaaaanks!!!!!!!

Answer 42

My Pleasure.