Question

help please

Answer 1

Please help

Answer 2

i replied it just a moment before

Answer 3

yeah i didnt get it so i re posted to get different help

Answer 4

@bookaholic do you know this one

Answer 5

I'm looking it over to see if I can solve it

Answer 6

ok

Answer 7

Roh how did you solve it?

Answer 8

i think we have to break the exponents of 2^20 lets get togather and break the power

Answer 9

2^20=1048576

Answer 10

is that the answer for a or B?

Answer 11

lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

Answer 12

niether and to get the number of bits youd multiply that by 2^3 or 8

Answer 13

Whattt

Answer 14

10^-10 x 1000
100 = 10^3

so
10^-10 x 10^3

add exponents...

10^-7 m

Answer 15

the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

Answer 16

@PinkPanda what one it that?

Answer 17

the first one

Answer 18

A ok do you ahve B yet?

Answer 19

ultraviolet rays is 0.000010 m

0.00000038<visible light<0.00000076

Answer 20

ok and do you have task 3?

Answer 21

one sec

Answer 22

ok

Answer 23

i gonna have to write this one out so hold on

Answer 24

the number of MB in Bytes are : 2^16 . 2^4
and i am trying to find out how to make it based on 2^3

Answer 25

Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x.
Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540).
model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x)
Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454)
Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

Answer 26

ok that last thing you posted^ what one is that for???

Answer 27

@PinkPanda

Answer 28

that the third task

Answer 29

what is for B on task 2?

Answer 30

To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb).

to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

Answer 31

What?????? Im so confused!!!!

Answer 32

oh wait I see how you did that ok i get it and that is for B?

Answer 33

yes that is for 2b

Answer 34

ok and then which one is for a and b on #3 that you did?

Answer 35

the really big message i did is for task 3 that one has no part a and b its just one q

Answer 36

oh ok thanks!

Answer 37

No problem!