Question

What is the value of 2x^-2y^-2 for x = 3 and y = -2?

a. 1/8
b. 72
c. 2(-6)-^4
d. 1/648

Answer 1

I got D...but i need to know if thats right...

Answer 2

\[2x^{(-2y ^{-2})}\]

Answer 3

is this what you mean?

Answer 4

can you confirm if the equation i wrote is right

Answer 5

Im trying to solve the exponents

Answer 6

yes i just want to make sure that the equation is right

Answer 7

can you see the mathematical form i gave you

Answer 8

its right except the -3 should be a negative 2

Answer 9

i don't have any -3 all the numbers are 2

Answer 10

2x^{(-2y ^{-2})}

Answer 11

Oh. It looked like a three for a second there. Sorry, your right

Answer 12

\[2x^{(-2y ^{-2})}\]

Answer 13

\[2(3)^{(-2(-2) ^{-2})}\]

Answer 14

agree with this step

Answer 15

I think the answer is D...is that right?

Answer 16

Whats your answer?