Question

Factor the trinomial: 3x2 - 7x - 6
(3x + 2)(x - 3)
(3x - 2)(x + 3)
(3x - 1)(x - 6)
(3x + 1)(x - 6)

Answer 1

please shown steps im really lost:(

Answer 2

ok.... here is my method

for a quadratic

\[ax^2 + bx + c\]

multiply a * c

in your question its 3 and - 6 3*-6 = -18

find the factors of - 18 that add to -7..... -9, 2

then do this

Answer 3

A similar method is below:

In a polynomial ax^2 + bx + c, find the product ac
In your case, 3x^2 - 7x -6, that woud be 3(-6) = -18

Now find two factors of ac that add up to the middle coefficint, b
In this case, find two factors of -18 that add up to -7
They are -9 and 2, since -9 * 2 = -18 and -9 + 2 = -7

Nowe break up the middle term, bx, into those two parts
In this case it's
3x^2 - 7x - 6 =
3x^2 - 9x + 2x - 6

Now factor by parts:
Factor a common factor out of the first two terms, and a common factor out of the last two terms:
3x(x - 3) + 2(x - 3)
Now factor out the common factor, (x - 3)
(x - 3)(3x + 2)

Answer 4

Use wolfram alpha