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Mathematics 26 Online
OpenStudy (anonymous):

help (fan and medal)

OpenStudy (anonymous):

OpenStudy (whpalmer4):

She has X to spent, and has already spent Y. That leaves her with X-Y left to spend. If guests cost $27 each, she divides the remaining amount of money (X-Y) by $27 to find out how many she can afford.

OpenStudy (anonymous):

so, basically she doesn't want to spend more than she has; if she spends it all, she'll have zero dollars left in her budget. So, I'd say the simplest way to setup your equation is: 0 = 5137 - 2086 - 27x .. then solve for x, where x would be the most number of guests she can have before going over budget.

OpenStudy (anonymous):

3051-27x

hero (hero):

27x = 5137-2086 27x = 3051 x = 3051/27

OpenStudy (anonymous):

hero (hero):

Did you find x?

OpenStudy (anonymous):

The answer is C, lol

hero (hero):

I was asking @GiGlgo3

OpenStudy (anonymous):

i thought C, is that right?

hero (hero):

@GiGIgo3

OpenStudy (anonymous):

because the situation can be modeled by a linear inequality of the form px + q < r, where p is the number of milligrams of caffeine per soda, q is the amount of caffeine Karla has already had today, and r is her recommended amount of caffeine.

OpenStudy (anonymous):

because, her total daily intake is already 230 , if she has x number of sodas, it will add 35 mg per soda to her daily intake, and her total daily intake should be less than 300mg. :)

OpenStudy (anonymous):

so, 230 + 35x should be less than 300. :)

OpenStudy (anonymous):

thanks @Hero

OpenStudy (anonymous):

thanks @ambius

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