Question

solve each system of equations by substitution

c+2d=12
c+d =2

Answer 1

alright, look at the second equation

1) let's get d by itself

Answer 2

so d=2-c?

Answer 3

c=2-d
and then replace c in the first equation
2-d+2d=12 => d=10
then replacing it in c
c=-8

Answer 4

good now in first equation , put that inplace of d

Answer 5

how?

Answer 6

so d=2-c

now substitute into first equation
c+2d=12

c+2(2-c)=12

Answer 7

ok

Answer 8

i got c =8
im way off

Answer 9

c+4-2c=12
-c+4=12
-c=12-4
-c=8
c=-8

Answer 10

ermagerwd im just getting more confused

Answer 11

its just confusing me more

Answer 12

A: c+2d=12 |>> in B c+d=2 = c=2-d substitute in A that c=2-d we will get
B: c+d=2 | -we will get in A c+2d=12 ;(c=2-d) then c in A turn to 2-d
means 2-d+2d=12 = 2+d=12 = d=12-2 = d=10 <get one
substitute in B c+d=2 ;(d=10) then c+10=2 = c=2-10 = c=-8
d=10 c =-8 i hope you not confuse now

Answer 13

haha yeah right im definatly confused

Answer 14

can u read my answer. it is simple

Answer 15

yeah but its confusing me all of this is i fluttering hate math it makes no fluttering sense to me

Answer 16

it seems that u did not but ur effort on it.