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show that (the integral of x/(3x^2+3) from x=5 to x=7 actually equals (1/6)[ln(150)-ln(78)]...the closest I can get is to show that the integral is equal to (1/2)[ln(150)-ln(78)] and I'm on the verge of thinking my teacher is wrong, however when I put both of these into wolfram, they came out to be o.11108 and 0.10898, which is very close, so please anyone...HELP ME BEFORE I GO CRAZY!
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