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4 over 5y + 2 =6 5 7 9 11
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do you mean \[4\div(5y+2)=6\] and solve for y?
if so you can simply input 5,7,9, and 11 into y until you get 6 on the left
Nono. I mean a fraction 4 over 5 y + 2
|dw:1360185376136:dw|
that is the same thing as 4/(5y+2)
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or \[4\div(5y+s)\]
2
do you mean (4/5)y +2 = 6 ?
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