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Mathematics 18 Online
OpenStudy (anonymous):

In the figure, the circle is inscribed in a regular pentagon. P,Q and R are points of contact, find x.

OpenStudy (anonymous):

|dw:1360246629990:dw|

OpenStudy (badhi):

|dw:1360246896292:dw| Is this helpful?

OpenStudy (anonymous):

why <RPQ=x?

OpenStudy (badhi):

Can you show that $$\Delta PQN\equiv\Delta RMQ$$

OpenStudy (anonymous):

SAS

OpenStudy (badhi):

Yes If so, RQ=PQ

OpenStudy (anonymous):

yup

OpenStudy (badhi):

So $$\Delta RQP$$ is a isosceles triangle, Thus <RPQ=x

OpenStudy (anonymous):

<RMQ=108 <MQR=180-108 / 2=36 <RQP=180-36*2=108 2x+108=180 x=36 ??

OpenStudy (badhi):

Yes. And the interesting fact is, this means PR\\MN.

OpenStudy (anonymous):

really?

OpenStudy (badhi):

why, a=x implies???

OpenStudy (anonymous):

ohh....i see... angles in alt. segment.... thank you very much:)

OpenStudy (badhi):

you're welcome :)

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