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In the figure, the circle is inscribed in a regular pentagon. P,Q and R are points of contact, find x.
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|dw:1360246629990:dw|
|dw:1360246896292:dw| Is this helpful?
why <RPQ=x?
Can you show that $$\Delta PQN\equiv\Delta RMQ$$
SAS
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Yes If so, RQ=PQ
yup
So $$\Delta RQP$$ is a isosceles triangle, Thus <RPQ=x
<RMQ=108 <MQR=180-108 / 2=36 <RQP=180-36*2=108 2x+108=180 x=36 ??
Yes. And the interesting fact is, this means PR\\MN.
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really?
why, a=x implies???
ohh....i see... angles in alt. segment.... thank you very much:)
you're welcome :)
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