(2^x+ 7)(x -5) -3 (x^2+ 5x)?
First, multiply out the two binomial on the left using FOIL. Then, distribute the -3. Then combine like terms.
Expand it out and collect like terms. Is that really 2^x and not x^2?
Also, when subtracting -3(x^2+5x) don't forget to change the sign on the 5x term as well. That's a frequent mistake! -3(x^2 + 5x) = -3x^2 -15x, NOT -3x^2 + 15x
Yeah, that must be x^2, not 2^x...
all sides of a triangle are known to be intergers. Two of the sides of the triangle are 8 and 12. How many different values are there for the third side?
Don't put new problems in existing threads, open new questions instead. And give medals if you expect additional help from people who answer your questions :-)
okay thank you :)
(x^2+ 7)(x -5) -3 (x^2+ 5x) = x^3 -5x^2 + 7x - 35 - 3x^2 - 15x Now collect like terms
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