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Find the y-intercept for the graph of the quadratic function.
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y + 4 = (x + 2)^2
ok, so the y intercept is when x = 0 right. so make x equal 0 and it becomes quite simple.
Hah its not simple to me. How would I make x equal to 0?
replace x with the number 0. solve for y. that gives the (0,y) plug what you get for y into the second value of the ordered pair to get the ordered pair of the y intercept point.
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So its -4,
ok, we start with y + 4 = (x + 2)^2 // then we assume x = 0 so y + 4 = (0+2)^2 y+4 = (2)^2 y + 4 = 4 y = 4-4 y = 0 so the y intercept is at (0,0)
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