Help?
Find the exact value of the real number y.

y = csc-1(-1)

Question

Help?
Find the exact value of the real number y.

y = csc-1(-1)

anonymous · Answer

you mean csc^(-1) of (-1)? it is unclear to know what the problem is

anonymous · Answer

csc = 1/sin
so we now have 
y = (csc(-1))^-1
so
y = (1/sin(-1))^-1
so
y = sin(-1)

anonymous · Answer

yes the arccsc of -1

anonymous · Answer

so the answer is 3pi/2?

directrix · Answer

What is the domain for the arccsc?

anonymous · Answer

whatt? the domain for it?

anonymous · Answer

+ -pi/2, everyone?

directrix · Answer

Why would an answer not be - pi/2?

anonymous · Answer

I think -pi/2

anonymous · Answer

yes, i think -pi/2

directrix · Answer

3*pi/2 would yield the -1 also. That's why I asked about the domain used by your text in defining the arccsc. Some books use ArcCsc and the arcCsc to distinguish between all possible solutions to the equation and then only those within the domain of the inverse.

anonymous · Answer

yes, Directrix is completely right,

directrix · Answer

I think I should have said "range" everywhere I posted "domain."

directrix · Answer

The -pi/2 is within the RANGE of the inverse of the cosecant.

directrix · Answer

Read more at this link: http://www.intmath.com/analytic-trigonometry/7-inverse-trigo-functions.php

anonymous · Answer

thank you