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Mathematics 25 Online
OpenStudy (anonymous):

Can some one help me with this math problem!!

OpenStudy (anonymous):

OpenStudy (anonymous):

the ratios of a 30 - 60 - 90 right triangle are \[1:\sqrt{3}:2\] for short leg : long leg : hypotenuse

OpenStudy (anonymous):

here your hypotenuse is 20 so short leg is 10 and the long leg is \(\frac{10}{\sqrt{3}}\)

OpenStudy (anonymous):

the side opposite the 30 degree angle is the short leg (since it is opposite the smallest angle) and the side opposite the 60 degree angle is the long leg, so your answer is \[\frac{10}{\sqrt{3}}\]

OpenStudy (anonymous):

oh never mind i got it the first one is 17.3 and then other one is 36.9

OpenStudy (anonymous):

can you help me with this one

OpenStudy (anonymous):

by answer was wrong anyway , it is \(10\sqrt{3}\)

OpenStudy (anonymous):

lol its ok

OpenStudy (anonymous):

square both sides, and get \[2x+3=6x-1\]

OpenStudy (anonymous):

solve get \[3=4x-1\]\[4=4x\] \[x=1\]

OpenStudy (anonymous):

ok what about the next one

OpenStudy (anonymous):

second one, square both sides, get \[\frac{b^4}{25}=16\] \[b^4=16\times 25\] \[b=\sqrt[4]{16\times 25}=\sqrt{4\times 5}=2\sqrt{5}\]

OpenStudy (anonymous):

oh ok it must be +2√5

OpenStudy (anonymous):

i forgot the \(\pm\)

OpenStudy (anonymous):

lol its k ok i have one more!!

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