Can some one help me with this math problem!!
the ratios of a 30 - 60 - 90 right triangle are \[1:\sqrt{3}:2\] for short leg : long leg : hypotenuse
here your hypotenuse is 20 so short leg is 10 and the long leg is \(\frac{10}{\sqrt{3}}\)
the side opposite the 30 degree angle is the short leg (since it is opposite the smallest angle) and the side opposite the 60 degree angle is the long leg, so your answer is \[\frac{10}{\sqrt{3}}\]
oh never mind i got it the first one is 17.3 and then other one is 36.9
can you help me with this one
by answer was wrong anyway , it is \(10\sqrt{3}\)
lol its ok
square both sides, and get \[2x+3=6x-1\]
solve get \[3=4x-1\]\[4=4x\] \[x=1\]
ok what about the next one
second one, square both sides, get \[\frac{b^4}{25}=16\] \[b^4=16\times 25\] \[b=\sqrt[4]{16\times 25}=\sqrt{4\times 5}=2\sqrt{5}\]
oh ok it must be +2√5
i forgot the \(\pm\)
lol its k ok i have one more!!
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