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OpenStudy (anonymous):
Find an equation for the tangent line to the graph of f(x)=ln(x^2 - 1) at the point where x = 2
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OpenStudy (campbell_st):
can you find the 1st derivative ..?
OpenStudy (anonymous):
2x/(x^2 -1) ?
OpenStudy (anonymous):
What step do I take next?
OpenStudy (campbell_st):
thats great... thats the equation for the slope of the tangent... so substitute x = 2 and you will have the slope at x = 2 you also need a point if you have x = 2 and substitute it into the original equation you will get a y value... then the the point slope formula for the equation of the tangent
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