please help! i don't understand this. If sin0=2/3, find the values of the other five trigonometric functions of 0. (the 0's have a slashed line through it)
i think in question it should be sin x.....please check it
no it says sin0, but the 0 has a dash through if. do you know what i mean by that?
it looks like the one on the top right corner
@erin512
YA ITS right now. the symbol is pronounced theta
oh okay sorry
\[\sin \theta =2/3\] \[\sin \theta=P/H\] where P stands for perpendicular and H stands for hypotenuse B denotes the base By pythagoras theorem... H^2=B^2+P^2 \[H=\sqrt{(P)^{2}+(B)^{2}}\] FROM THIS.. \[B=\sqrt{(H)^{2}-(P)^{2}}\] \[B=\sqrt{9-4}\] \[B=\sqrt{5}\]
\[\cos \theta=B/H\] \[\cos \theta=\sqrt{5}/3\]
\[\tan \theta=P/B\] \[\tan \theta=2/\sqrt{5}\]
\[\sec \theta=1/(\cos \theta)\] \[\cot \theta=1/(\tan \theta)\] \[\csc \theta=1/(\sin \theta)\]
i hope u can find them now......
what am i trying to find now? thanks for all the help. i'm sorry, i'm so lost in this unit
@nitz
put the values of \[\cos \theta,\tan \theta,\sin \theta \] in THE ABOVE THREE expressions to find the values of these three angles respectively...
not these three angles......it should be other three angles..... ie \[\sec \theta ,\cot \theta,\csc \theta \]
cosθ,tanθ,sinθ = 0.75, 0.89, 0.67. is this correct?
@nitz
i'm not sure what the final answer would be
oh are those the first 3 values its looking for?
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