Mathematics
8 Online
OpenStudy (anonymous):
.
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OpenStudy (anonymous):
I did
OpenStudy (lstrasmann):
I did last year. Maybe I can help
OpenStudy (lstrasmann):
you mean like\[Simplify \sqrt{5x^2}\]
OpenStudy (lstrasmann):
OK, what's teh problem?
OpenStudy (lstrasmann):
the*
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OpenStudy (lstrasmann):
OK.
OpenStudy (lstrasmann):
\[\sqrt{20}\]=\[2\sqrt{5}\]
OpenStudy (lstrasmann):
\[\sqrt{70x^2}\]=sqrt(2)*sqrt(5)*sqrt(7)*abs(x)
OpenStudy (lstrasmann):
Oops. thats\[\sqrt{2} \times \sqrt{5} \times \sqrt{7} \times \left| x \right|\]
OpenStudy (anonymous):
your fine!
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OpenStudy (lstrasmann):
Uhm.. number 3 comes up like this:
OpenStudy (lstrasmann):
Are you still here?
OpenStudy (anonymous):
you fine
OpenStudy (lstrasmann):
OK, good. I think @mariisol was talking to me. But I have no idea what she's talking about. xD
OpenStudy (anonymous):
I'am bi
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OpenStudy (lstrasmann):
Okay, lets ignore her and move on
OpenStudy (jamesj):
mariisol, irrelevant. Please don't spam again.
OpenStudy (lstrasmann):
No, it's \[2\sqrt{5}\]because we have \[\sqrt{20}=\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5}\]
OpenStudy (lstrasmann):
Simplify sqrt(4) to get 2
OpenStudy (lstrasmann):
then you can't simplify sqrt(5) to get a whole number. so we leave it as 2sqrt(5)
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OpenStudy (lstrasmann):
OK, so moving on
OpenStudy (lstrasmann):
Here is number 4:
OpenStudy (lstrasmann):
OK, you're welcome.