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Mathematics 8 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

I did

OpenStudy (lstrasmann):

I did last year. Maybe I can help

OpenStudy (lstrasmann):

you mean like\[Simplify \sqrt{5x^2}\]

OpenStudy (lstrasmann):

OK, what's teh problem?

OpenStudy (lstrasmann):

the*

OpenStudy (lstrasmann):

OK.

OpenStudy (lstrasmann):

\[\sqrt{20}\]=\[2\sqrt{5}\]

OpenStudy (lstrasmann):

\[\sqrt{70x^2}\]=sqrt(2)*sqrt(5)*sqrt(7)*abs(x)

OpenStudy (lstrasmann):

Oops. thats\[\sqrt{2} \times \sqrt{5} \times \sqrt{7} \times \left| x \right|\]

OpenStudy (anonymous):

your fine!

OpenStudy (lstrasmann):

Uhm.. number 3 comes up like this:

OpenStudy (lstrasmann):

Are you still here?

OpenStudy (anonymous):

you fine

OpenStudy (lstrasmann):

OK, good. I think @mariisol was talking to me. But I have no idea what she's talking about. xD

OpenStudy (anonymous):

I'am bi

OpenStudy (lstrasmann):

Okay, lets ignore her and move on

OpenStudy (jamesj):

mariisol, irrelevant. Please don't spam again.

OpenStudy (lstrasmann):

No, it's \[2\sqrt{5}\]because we have \[\sqrt{20}=\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5}\]

OpenStudy (lstrasmann):

Simplify sqrt(4) to get 2

OpenStudy (lstrasmann):

then you can't simplify sqrt(5) to get a whole number. so we leave it as 2sqrt(5)

OpenStudy (lstrasmann):

OK, so moving on

OpenStudy (lstrasmann):

Here is number 4:

OpenStudy (lstrasmann):

OK, you're welcome.

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