last of algebra 2 help

Question

anonymous · Answer

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anonymous · Answer

for the first one you just plug in the numbers 1-5 for n to get the answer

anonymous · Answer

for the second one. remember that when a number has the subscript. $$_{n-1}$$ its the number BEFORE

anonymous · Answer

i figured out the first one. how do i start the second one?

anonymous · Answer

its hard to explain over the computer. the answer is the second one. but in essence. if a1 is equal to 15. then 2 times that minus 4 is the next number in that sequence. and its true for all the numbers.

anonymous · Answer

wait thats for the second problem?

anonymous · Answer

ya. the second problem's answer is the b or the second bullet point. 
lemme try to explain for your knowledge

anonymous · Answer

$$a_{1} $$ = 15
$$a_{2} $$ = 26
$$a_{3} $$ = 48

and so on. if it says $$a_{n-1} $$  then its the number before. for example. if we took the number 26. $$a_{n-1} $$ is 15. and so on.

anonymous · Answer

since $$a_{2-1} $$ = $$a_{1} $$ and it says $$a_{1} $$  = 15. they're not equations. there a different form of variables. such as x y and z