Question

5x + 7=> 2 and 10x <=30

6x + 7 => 25 or 2x - 8 < -4

4x + 10 <= 6 or 5x - 6 =>14

37 <= 8x - 3 <= 61

http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v10/05_03_10e.jpg

Answer 1

Just solve for x:

5x+7 =>2 and 10x <= 30
-7 -7 and /10 /10

5x => -5 and x <= 3
/5 /5

x => -1 and x <= 3

Just do that for all of them. :o)

Answer 2

:s

Answer 3

?

Answer 4

So its the first one?

Answer 5

Yes, now try and do the other ones.

Answer 6

Im stuck :S

Answer 7

Someone not in your class can't generally see the contents of the link you posted.

Answer 8

Okay, for number 2:

6x + 7 => 25 or 2x - 8 < -4

Just look at them seperately:

6x+7 => 25
-7 -7

6x => 18
/6 /6

x => 3

Can you try and solve 2x-8<-4?

Answer 9

\[6x + 7 \ge 25\] or \[2x - 8 < -4\]
Subtract 7 from both sides
\[6x \ge 18\]Divide by 6
\[x \ge 3\]
OR
\[2x-8 < -4\]
Add 8 to both sides
\[2x < 4\]Divide both sides by 2
\[x<2\]
So
\(x \ge 3\) or \(x<2\)

Answer 10

Just do the same thing to both sides. If you multiply or divide by a negative number, you change the direction of the inequality.

Answer 11

So my answer is either C or D?