Question

write sinx in termss of secx

Answer 1

clue secx=(1/cosx)

Answer 2

Another hint: sin²x + cos²x = 1

Answer 3

\(\sec x = \dfrac{1}{\cos x}\) so \(\sec^2 x = \dfrac{1}{\cos^2 x}\)

Answer 4

Still don't get it? @Leemah!

Answer 5

Not really, I have just started my trig and precal class. I had straight A's in all my precious math classes, but I am really having difficulty with identities and trig in general. I have never seen it before. I have the answer as \[\sqrt{\sec x-1}/\sec x\]
but don't know how to get there.