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what is the derivative with respect to time of: x*e^[i(w*t-a)]
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let u=i(wt-a) y=xe^u find du/dt then dy/du
If I write the formula as a function f of t, I get:\[f(t)=x e^{i(wt-a)}\] Is the number i in the formula meant as sqrt(-1)? That would make it a complex-valued function. It doesn't matter much, though. We consider all other numbers than t as constants. Also, the derivative of the exponential function e^t is e^t itself. So differentiating your function wouldn't change it much, only use the following rules to get the answer: 1. (e^t)' = e^t (it is an exponential function) 2. (c*f(t))' = c*f'(t) (the x returns in the derivative unchanged) 3. Chain Rule (you need it for the exponent)
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