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Why is the charge on the outer surface of the outermost shell neutral?
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@phi
Oh I forgot to add some info haha
a charge of +Q is placed on the outermost shell a charge of -Q is placed on the solid innermost sphere
and the question is: What will be the charge on the outer surface of the outermost shell?
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and the answer is 0
Try using Gauss's Law
|dw:1360454418580:dw| \[\phi_{net}=E\cdot A=\frac{Q_{inside}}{\epsilon_0}\]
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