Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

Why is the charge on the outer surface of the outermost shell neutral?

OpenStudy (anonymous):

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

Oh I forgot to add some info haha

OpenStudy (anonymous):

a charge of +Q is placed on the outermost shell a charge of -Q is placed on the solid innermost sphere

OpenStudy (anonymous):

and the question is: What will be the charge on the outer surface of the outermost shell?

OpenStudy (anonymous):

and the answer is 0

OpenStudy (phi):

Try using Gauss's Law

OpenStudy (anonymous):

|dw:1360454418580:dw| \[\phi_{net}=E\cdot A=\frac{Q_{inside}}{\epsilon_0}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!