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Find sin q if q is an angle in standard position and the point with coordinates (4, 3) lies on the terminal side of the angle. I don't understand what I'm suppose to be doing here.
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Basically you have this grid here: |dw:1360457129702:dw| So it just wants you to find angle X here, then evaluate it for sin x. (Assume q = x)
So do I do sin(4)?
No, you want the angle X first, remember that tan(X) = y/x = 3/4. So it follows that arctan or tan^-1(3/4) = 36.8698976 degrees. Then you just find sin(36.8698976) to get your answer.
Oh okai I didn't know that, thank you c:
No problem.
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