How to solve this? Multiple choice.
(2x + y) + (3x + y) = 4x + 10 2x + y = 3x + y Solve the system
5x = 2y?
You didn't exactly do that correctly.
You have to subtract the proper numbers from both sides, not add
still confused?
You have two equations. Solve one of them for x or y, then plug that value into the other and solve
what value though?
Here, I'll help you out: 2x + y = 3x + y y - y = 3x - 2x 0 = x so x = 0. Plug that into the first equation and solve for y.
Thats still confusing? You wont get a answer?
Yes, you will bro. You're just not seeing it for some reason.
(2x + y) + (3x + y) = 4x + 10 2x + 3x + y + y = 4x + 10 (2 + 3)x + 2y = 4x + 10 5x + 2y = 4x + 10 5x - 4x + 2y = 10 x + 2y = 10 Now plug in x = 0 and finish solving for y.
y = 5?
Yes, but you should have been able to do it without my help.
it was just confusing the way you put it. sorry.
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