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Tje ratio of the sides of a right triangle are 5:12:13. What is the tangent of the larger acute angle of the triangle?
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Let me draw it for you, but first understand that given a right triangle, its hypotenuse (the angle opposite the right angle) is always the longest... |dw:1360509864232:dw| Where k is some positive constant.
Okay, the larger acute triangle is opposite the larger of the two legs. So this is the angle in question: |dw:1360509988585:dw| Now what's tan A?
12 over 5, then divide, right?
12/5 should probably suffice, unless a decimal answer is called for.
|dw:1360510227792:dw12/5=2.4
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Either of those. You're right :)
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