Question

Find the vertex of the parabola by completing the square. x^2-6x+8=y

Answer 1

First, set it equal to 0, then subtract 8 from both sides to make it x^2-6x=-8

Answer 2

After that you want to add half of the coefficient of the x term squared to both sides (if that makes any sense). So half of 6 is 3. 3 squared is 9. After this you'll have x^2-6x+9=1

Answer 3

Now you have a perfect square term on the left which factored will give you (x-3)^2=1

Answer 4

Now to find the vertex, you look at it in this form as a(x-h)^2+k with vertex (h,k)

Answer 5

So your vertex will be (3,-1)

Answer 6

got it thank you

Answer 7

No problem!