You can not cancel out "a" since we don't know if that'll be equal to 0 or not.
=> a^2 ( (3b)^2 -1) = 0
OpenStudy (dls):
??
OpenStudy (dls):
\[\LARGE 9a^2 b^2-3a^2=0\]
\[\LARGE 3a^2(3 b^2-1)=0\]
a=0 b=0
and other two real values
and a and b are those ellipse equation wale constant here..how can it be 0
OpenStudy (shubhamsrg):
So a is not 0, that means you can cancel it out
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OpenStudy (shubhamsrg):
so b= +- sqrt(1/3)
OpenStudy (dls):
how do we know a is not 0
OpenStudy (shubhamsrg):
SInce it denotes length of major axis of ellipse!
OpenStudy (dls):
yeah so point ellipse :P
ellipse doesn't exist
OpenStudy (dls):
its not wrong mathematically..
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