I've got a calc 1 question. Find an equation of the tangent line to the curve at the given point.

y=3x^2-x^3 at point (1,2)..

I got this at y'=-3x^2+6x. Then I plugged the x and y values into the point slope equation along with the derivative I found earlier to get.
y-2=-3x^2+6x(x-1) and this is where I am stuck. I feel like I'm doing something wrong at this point.

Question

I've got a calc 1 question. Find an equation of the tangent line to the curve at the given point.

y=3x^2-x^3  at point (1,2)..

I got this at y'=-3x^2+6x. Then I plugged the x and y values into the point slope equation along with the derivative I found earlier to get.
y-2=-3x^2+6x(x-1) and this is where I am stuck. I feel like I'm doing something wrong at this point.

anonymous · Answer

Okay, once you have the derivative, plug in the point's x value to get slope of your tangent line. Then, you can use that to create the equation in the form:

y-2 = m(x-1)

anonymous · Answer

Oh wow, that simple huh lmao. Thanks a ton! :)

anonymous · Answer

No problem kiddo.