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\[3\sqrt{x+4}-2=13\]
First, get the radical by itself. \[\sqrt{x+4} = 5\] Now square both sides, then solve for the x.
x=1?
Not exactly, first you want to square both sides \[\sqrt{x+4} = 5\] \[x+4 = 25\] x = 21
Oh, I see! I wasn't sure what you meant by "both sides" ;P
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21+4=25 so it all makes sense ;P
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