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$4^{\frac{1}{x}-2}= \frac{(ln \sqrt{e})}{2}$
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\[4^{\frac{1}{x}-2}= \frac{(ln \sqrt{e})}{2}\] (If you put \ [ and \ ] (no spaces) instead of $ around your expressions it should format them)
Why not take the log of both sides, then solve for x?
Remember that \[\log a^n = n \log a\]
Also, try writing that radical sign with exponential notation instead and see if any ideas come to you...
Don't forget that \(a^{-n} = \dfrac{1}{a^n}\)
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