Question

Can someone help me solve a problem?

Answer 1

\[(1/10)^{y}=100^{y+3}\]

Answer 2

help!

Answer 3

We already did this one.

Answer 4

\[\Large (1/10)^{y}=100^{y+3}\]


\[\Large \left(10^{-1}\right)^{y}=\left(10^{2}\right)^{y+3}\]


\[\Large 10^{-y}=10^{2(y+3)}\]


I'll let you finish

Answer 5

thank you!

Answer 6

np

Answer 7

wait I'm confused where I go fro here? Do I set the exponents equal to each other or what?:)

Answer 8

yes

because the bases are equal, the exponents are equal

Answer 9

-y = 2(y+3)

solve for y

Answer 10

-2

Answer 11

yep, the answer is y = -2