Could someone show me how to do these 5? 1. 9x^2 (x-2)-8x(x-2) 2. 2x^3 –x^2– 8x + 4 3. 3y^3– 6y^2 + 4y – 8 4. 4m^2+5m-9 5. 5p ^2+23p-42
What is the question asking? To factor or simplify?
factor
ok, the first one gives you the following: 9x^2 (x-2)-8x(x-2) // factor out the (x-2) (x-2) * (9x^2-8x) // you can also factor out an x from 9x^2-8x x*(x-2)*(9x-8)
@tomo so (x-2)*(9x^2-8x) is the answer?
well you can still factor an x out of the (9x^2-8x) so you would have (x-2) * x(9x-8)
@tomo i just need #2 and #3 cuz i ended up figuring out how to do 4 and 5
2x^3 –x^2– 8x + 4 x^2(2x-1) + 4*(-2x+1) x^2(2x-1) -4(2x-1) // pull out a (2x-1) (2x-1)(x^2-4)
3y^3– 6y^2 + 4y – 8 3(y^2)(y-2) + 4(y-2) //pull out a y-2 (y-2)(3y^2+4)
@tomo could you show me #3 cuz i think i got it but i wanna make sure
im sorry i ment #2
// what we start with 2x^3 –x^2– 8x + 4 // pull out a x^2 out of the first two terms. pull out a 4 out of the second two terms. x^2(2x-1) + 4*(-2x+1) // pull out a -1 out the second two terms. this reverses the signs on the two last terms. so instead of -2x+1 you have -(2x-1). this allows you to have a common factor of (2x-1) x^2(2x-1) -4(2x-1) // pull out the common factor of (2x-1) (2x-1)(x^2-4)
omg im so sorry i keep getting my numbers all mixed up, ur probably annoyed cuz u just show me how to do #2 lol. i needed you to show me 4. sorry again @tomo
no problem. // this one is a bit more confusing though.
@tomo i got (4m+9)m-1)
ok, so we start with 4m^2+5m-9 // for some reason, break up the 5m into 9m-4m. I don't know why, but it works. 4m^2+9m-4m-9 // so now this is something we can work with. pull a negative out of the -4m-9. 4m^2+9m-(4m+9) // like you got. (4m+9)(m-1)
hope that helps. gotta go to sleep now.
@tomo dude thank you so much, you have no idea how big of a help you were. goodnight!
Join our real-time social learning platform and learn together with your friends!