Question

find the zeros of the function y=x^2-4x+3 by factoring

Answer 1

For x^2+bx+c, find two numbers that multiply to equal c, and add up to b.

So find two numbers that multiply to equal +3, and add up to equal -4.

Answer 2

Hint: they'll both have to be negative.

Answer 3

1.5?

Answer 4

3 and 1

Answer 5

They both have to be negative... -3 and -1. (-3)*(-1) = 3 and -3 + (-1) = -4.
Now write it as
y = (x - 3)(x - 1)

Answer 6

ok

Answer 7

This is confusing

Answer 8

From
y = (x - 3)(x - 1), to find the zeroes, we let y = 0

0 = (x - 3)(x - 1)

Either x-3=0 or x-1=0

x-3 = 0 then x = 3
x-1 = 0 then x = 1