Question

Factor jm + jn + km + kn.

Answer 1

is the answer (n+j)(k+m)

Answer 2

Let's find out

(n+j)(k+m)

n(k+m) + j(k+m)

nk + nm + jk + jm


So we have kn, but no km

we have jm, but no jk

So it's not correct

Answer 3

so it is (j+m)(n+k)

Answer 4

(j+m)(n+k)

j(n+k) + m(n+k)

jn + jk + mn + mk

So we have an mn term here, but that's not in the original expression

so that's wrong too

Answer 5

Hint:

jm + jn + km + kn

j(m + n) + k(m + n)

Answer 6

so it is this (j + k)(m + n)

Answer 7

yep

Answer 8

okay can u help me again

Answer 9

sure

Answer 10

okay I post another one '