Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

write the polynomial in factored form 4x^3+8x^2-96x

OpenStudy (anonymous):

Trial and error. Test points for x and when the polynomial becomes 0 for a value of x, then you will get this. (x-a) where a is the x-value that made the polynomial equal to zero.

OpenStudy (anonymous):

You will then divide (x-a) with the polynomial to get the rest of the polynomial. Combine the two and that will be your factored form.

hartnn (hartnn):

or, if you can factor quadratic equations, this one will be easy, can you ?

OpenStudy (anonymous):

Yep you can.

OpenStudy (anonymous):

Do what hartnn told you to do.

OpenStudy (anonymous):

so would it be 4x(x-4)(x+6)?

hartnn (hartnn):

\(\checkmark \) good work :)

OpenStudy (anonymous):

does that mean yes or no lol

hartnn (hartnn):

yes, correct :P

OpenStudy (anonymous):

one last question for ya

OpenStudy (anonymous):

what would be the end behavior of y=3(x+2)^3-3?

hartnn (hartnn):

do you know what all we need to find to get the end behavior ?

OpenStudy (anonymous):

the main question was to graph the equation 3(x+2)^3-3 and describe end behavior so im guessing it's referring to the 1st term after you factor the equation

hartnn (hartnn):

you need to find where the graph is concave up, and concave down...since you've graphed it, you would notice that it goes up from right side of a point and goes down from left side from that point, right ?

OpenStudy (anonymous):

im double checking my graph wasnt to confident in my answer but yeah thats what i got

OpenStudy (anonymous):

so final answer is up down

hartnn (hartnn):

its down up. we start from left side... http://www.gradeamathhelp.com/polynomials.html

OpenStudy (anonymous):

oh woops lol if i could show u my graph i would it is correct i typed it wrong thank you so much :)

hartnn (hartnn):

welcome ^_^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!