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OpenStudy (anonymous):
ab + 4 + a + 4b
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OpenStudy (anonymous):
is the answer ab(ab+4)a(a+4b)
OpenStudy (anonymous):
ya can u raw down how I would do that
OpenStudy (anonymous):
draw sorry
Directrix (directrix):
Yes, I'll work this problem step by step and then you can do the next one.
OpenStudy (anonymous):
okay thank u
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OpenStudy (anonymous):
ya i get that
OpenStudy (anonymous):
what u mean
Directrix (directrix):
>> is the answer ab(ab+4)a(a+4b) No
OpenStudy (anonymous):
okay how do u do it
Directrix (directrix):
ab + 4 + a + 4b =
ab + a + 4b +4
Agree? @Shannon20150
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OpenStudy (anonymous):
agreed how do u solve it
Directrix (directrix):
ab + a + 4b +4 =
(ab + a) + (4b + 4) =
a*(b + 1) + 4*(b + 1) =
Agree so far?
OpenStudy (anonymous):
yes
Directrix (directrix):
(b + 1) is a common factor
a*(b + 1) + 4*(b + 1) =
(b + 1) [a + 4] =
(b + 1) (a + 4) --> Answer
Agree?
OpenStudy (anonymous):
yes thank u so much
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Directrix (directrix):
I did that one. So, may I write a problem for you to do to practice. Practice is the only way I know to learn to factor.
Directrix (directrix):
Or, do you have another on your homework you want to do?
OpenStudy (anonymous):
im posting one that i need u to c if it is right
Directrix (directrix):
Okay
OpenStudy (anonymous):
i posted it
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Directrix (directrix):
Okay, I didn't see it.
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