Please Help! Need One Last Question! A tugboat goes 160 miles upstream in 20 hours. The return trip downstream takes 10 hours. Find the speed of the tug boat without a current and the speed of the current.
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OpenStudy (aravindg):
so tell me what is speed during upstream journey
OpenStudy (anonymous):
160miles? @AravindG
OpenStudy (aravindg):
speed=distance/time
OpenStudy (anonymous):
??????? still confused can you write the equation out please..... @AravindG
OpenStudy (aravindg):
what is distance=160 miles
time =20 hrs
speed =?
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OpenStudy (anonymous):
would it be 8 @AravindG
OpenStudy (aravindg):
yep :)
OpenStudy (anonymous):
Is that the answer to the speedof the tugboat with out a current? @AravindG
OpenStudy (aravindg):
no can u find speed of return trip now?
OpenStudy (anonymous):
Would the answer be 16 for the current? @AravindG
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OpenStudy (aravindg):
hey i think we should do it by another method
OpenStudy (anonymous):
so those answers are incorrect? @AravindG
OpenStudy (aravindg):
Let s= the speed of the tugboat without a current
Let c= the speed of the current
Going upstream:
160=(s-c) *20
Going downstream:
160=(s+c)*10
OpenStudy (aravindg):
now find s+c and s-c from these 2 eqns
OpenStudy (anonymous):
For the first equation i multiply 20 to both s and c? @AravindG
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OpenStudy (aravindg):
for first eqn divide by 20
OpenStudy (anonymous):
so is it 8=(s-c) @AravindG
OpenStudy (aravindg):
ya what abt second eqn ?
OpenStudy (anonymous):
16=(s+c) @AravindG
OpenStudy (aravindg):
yep :)
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OpenStudy (aravindg):
now add both these to get c
OpenStudy (aravindg):
then u will get speed of current !
OpenStudy (anonymous):
so 24? @AravindG
OpenStudy (aravindg):
try again ?
OpenStudy (anonymous):
2? @AravindG
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OpenStudy (aravindg):
try again ?
OpenStudy (anonymous):
Ya i dont know @AravindG
OpenStudy (aravindg):
(s-c) = 8
+ (s+c) =16
__________
OpenStudy (aravindg):
sorry u get s vakue when u add not c ...anywas find s
OpenStudy (aravindg):
so can u add it now ?
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OpenStudy (anonymous):
8? @AravindG or 24
OpenStudy (aravindg):
can u show ur addition using draw button below ?
OpenStudy (anonymous):
i mean 12 @AravindG
OpenStudy (aravindg):
\[\checkmark \]
OpenStudy (aravindg):
now substitute s value in any of the above eqns to get c :)
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OpenStudy (anonymous):
4? @AravindG
OpenStudy (aravindg):
\[\checkmark \]
OpenStudy (anonymous):
THANK YOU VERY MUCH! i have one more question can you help me on my next problem?
OpenStudy (anonymous):
@AravindG
OpenStudy (aravindg):
dont u need speed of tug boat without current ?
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OpenStudy (anonymous):
yes i do.... how do we figure that out?? @AravindG
OpenStudy (aravindg):
my mistake :P speed of tug boat in still water is s=12 :P