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If A is a subset of B, then P (A and B) =
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well P = B, hmm seems right since A includes bits of B
By definition, the "power set" of A, P(A), is the collection of all subsets of the set A. Since A is a subset of B, all elements of A belong to B, and thus all subsets of A (i.e. P(A)) belong to all subsets of B (i.e. P(B)). In other words, everything A has, B also has. Then every combination of something A has is a combination of something B has.
B = (2,3,4,5,6,7,8,9) A = (3,5,7,9) P = (2,3,4,5,6,7,8,9)
Wow, big words :D
B=(1,2,3,5,7,8,9) A=(1,3,5,7,9) P=(1,2,3,5,7,8,9)
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Exactly so thus P = B
Lol it was confusing me
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