Question

I am a bit stumped about this one:
A jet with mass m = 90000.0 kg jet accelerates down the runway for takeoff at 1.6 m/s2.

3) Once off the ground, the plane climbs upward for 20 seconds. During this time, the vertical speed increases from zero to 24.0 m/s, while the horizontal speed increases from 80.0 m/s to 98.0 m/s.

5) After reaching cruising altitude, the plane levels off, keeping the horizontal speed constant, but smoothly reducing the vertical speed to zero, in 13.0 seconds.

What is the net vertical force on the airplane as it levels off?

Answer 1

Force = mass times acceleration; what is the vertical acceleration?

Answer 2

and net might imply that we subtract the acceleration of gravity from it

Answer 3

since constant speed equals zero acceleration; the forward force should be mass*zero

the vertical force is again calculated tho using the same concepts as the first time ....

Answer 4

Thanks that really helped. I added the last part of the question, which is the only one I haven't been able to solve.

Answer 5

Okay I edited it to only include the question I had originally left out. Thanks in advance for your help!

Answer 6

g/m

Answer 7

link to my g/m http://www.physicsclassroom.com/class/newtlaws/u2l2b.cfm