Question

Ok so I got this question wrong. What is the way to solve this system of equations?

{2(y - 6) = 3y + 4(x-5)
{2(4x + 3) - 5 = 2(1 - y) + 5x

Answer 1

whenever you simplified the equations what did you get

Answer 2

I distributed the numbers that were near the parentheses first.

Answer 3

after simplification i got
first equation:
y + 4x = 8

second equation :
3x+2y = 1

then y = 8 - 4x so putting the first into the second
3x + 2(8 - 4x) = 1
3x + 16 - 8x = 1
-5x = -15
x = 3

y = 8 - 4(x)
y = 8 - 4(3)
y = 8 - 12
y = -4

Answer 4

first equation:
2(y - 6) = 3y + 4(x-5)

2y - 12 = 3y + 4x - 20
-12 + 20 = 4x + 3y - 2y
8 = 4x + y
or
y + 4x = 8

second equation
2(4x + 3) - 5 = 2(1 - y) + 5x

8x + 6 - 5 = 2 - 2y + 5x
8x - 5x + 2y = 2 + 5 - 6
3x + 2y = 1

Answer 5

........Oh ok you make it seem so clear. I don't know how I wsas mixing it up. Must be too much stress. Thank you so much @Davidjohn

Answer 6

no problem, lots of practice. It's easy to mix up a number when there are so many