Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Find the zeros of the function. f(x) = 6x^3 + 18x^2 + 12x

OpenStudy (anonymous):

Here are the answer choices: 0, 1, and 2 0, -1, and -2 -1 and -2 1 and 2

OpenStudy (anonymous):

Pull 6x out and then find the roots. so make f(x) = 6x(x^2 + 3x + 2)

OpenStudy (anonymous):

Simplify that and you should be able to find your roots.

OpenStudy (anonymous):

So, are the roots 1 and 2?? (:

OpenStudy (anonymous):

you also have to remember that you have a 6x, if x = 0, then doesn't the function also equal zero? Also, remember, the equation is this (x-a)(x-b) = 0 in order to get (x+c), the actual value of the zero has to be negative.

OpenStudy (anonymous):

Oh, yeah!! So, it's 0, -1, -2?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Thank you so so much for your help!!! You are a lifesaver!! :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!