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Find the zeros of the function. f(x) = 6x^3 + 18x^2 + 12x
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Here are the answer choices: 0, 1, and 2 0, -1, and -2 -1 and -2 1 and 2
Pull 6x out and then find the roots. so make f(x) = 6x(x^2 + 3x + 2)
Simplify that and you should be able to find your roots.
So, are the roots 1 and 2?? (:
you also have to remember that you have a 6x, if x = 0, then doesn't the function also equal zero? Also, remember, the equation is this (x-a)(x-b) = 0 in order to get (x+c), the actual value of the zero has to be negative.
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Oh, yeah!! So, it's 0, -1, -2?
yup
Thank you so so much for your help!!! You are a lifesaver!! :D
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