How many rational roots does x4 + 3x2 + 2 = 0 have?
0
1
2
4
Caught between 0 and 2 but not sure...
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OpenStudy (noelgreco):
Can you factor the expression?
OpenStudy (anonymous):
ummmm no, I dont know how to...
OpenStudy (noelgreco):
Are you allowed to use a graphing calculator, and if so do you have one?
OpenStudy (anonymous):
no just a regular calculator
OpenStudy (noelgreco):
Have you factored quadratics such as x^2 -7x+12
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OpenStudy (anonymous):
its (x-3)(x-4)
OpenStudy (noelgreco):
Yes, good.
Can you factor x^2+3x+2?
OpenStudy (anonymous):
x(x+5)
OpenStudy (noelgreco):
Oops. If you expand your answer it gives x^2+5x.
It should be (x+2)(x+1), and your original question would factor to (x^2+2)(x^2+1).
Can you find any values of x that would make that product = 0?
I have to run - at least for a while.
OpenStudy (anonymous):
ok is it 2
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OpenStudy (anonymous):
wait none of them equal to 0
OpenStudy (anonymous):
well thanks for your time I'm going to go know but whenever you have the chance to answer, I would appreciate it, bye :)
OpenStudy (noelgreco):
You say the answer is 2. Give me a value of x that makes x^2 + 1 = 0