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A polynomial function f(x) degree 4 with real coefficients has zeros of 3 and 5-i. Explain why one of the remaining zeros must be a real number. PLEASEEE HEELP!
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Each imaginary solution has to come with its complex conjugate, in this case, (5+i). Since complex solutions come in pairs, and the other solution is real, the fourth solution must be real. (If it were complex, it would require its complex conjugate.)
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