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OpenStudy (anonymous):
solve sinx+2sinxcosx=0 for 0 degrees ≤ x ≤ 180 degrees
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OpenStudy (aravindg):
sin x+2sinx cos x=sin x(1+2cos x )=0
implies sinx=0 or 1+2cos x=0
solve :)
OpenStudy (anonymous):
Thank you c:
OpenStudy (anonymous):
so sin0(1+2cos0) = 0?
OpenStudy (aravindg):
not that way solve each separately
sin x=0
x=?
1+2cos x =0
x= ?
OpenStudy (aravindg):
note that you need to report a general value in 0 degrees ≤ x ≤ 180 degrees
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OpenStudy (anonymous):
I don't get it :l
OpenStudy (aravindg):
ok i will do first one
sin x=0
means x=0 or pi
OpenStudy (anonymous):
oh >_<
OpenStudy (aravindg):
can u do 2nd one ?
OpenStudy (anonymous):
1+2cos(pi)?
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OpenStudy (aravindg):
first solve for cos x
OpenStudy (anonymous):
Would it not be pi? :l
OpenStudy (aravindg):
1+2cos x=0
cos x= ?
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
so 1+2cosx=3?
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OpenStudy (aravindg):
............
OpenStudy (anonymous):
No? >_<
OpenStudy (anonymous):
I'm not good at these >_<
OpenStudy (aravindg):
1+2cos x=0
cos x=?
OpenStudy (anonymous):
Ohhhh 3 cuhs all of that equals 0?
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OpenStudy (anonymous):
cos x = 3 I mean
OpenStudy (aravindg):
???
OpenStudy (anonymous):
>_<
OpenStudy (aravindg):
assume cos x=y
1+2y=0
y= ?
OpenStudy (anonymous):
-1/2?
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OpenStudy (aravindg):
exactly !! well done :)
OpenStudy (aravindg):
finally :P
OpenStudy (anonymous):
lmao sorry I didn't get it cx
OpenStudy (anonymous):
Well at first cx
OpenStudy (anonymous):
So how would my final answer look? :l
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OpenStudy (aravindg):
COS X=-1/2
x= 120 degree or pi-pi/3
OpenStudy (anonymous):
oh okai c: thank you c:
OpenStudy (aravindg):
yw :)
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