Question

A 2.05m--tall basketball player takes a shot when he is 6.02m from the basket. If the launch angle is 27 degrees and the ball was launched at the level of the player’s head, what must be the release speed of the ball for the player to make the shot? The basket is 3.05m above the floor.

Answer 1

basket 3.05m -player 2.05m =1m

Answer 2

I need the velocity.

Answer 3

27 degrees = 3.703 +- .00703703

Answer 4

h = 1m
1m x 3.704 = 3 .704

Answer 5

I got it.

Answer 6

http://www.youtube.com/watch?v=0OV1E9M9Kkc this the same as formal

Answer 7

at 12 mins of the video is v= .....