Question

What are the real zeros of f(x) = x^3 – 3x^2 – 4x?

A. 0, 1, 4 B. 1, -1, 4 C. -1, 0, 4 D. 1, 0, -4

Answer 1

So, we need to factor the equation to find the answers.\[x(x^2-3x-4)\]So looking at this we can tell that one of the factors is 0.
Now we just need to factor that inner equation and we get \[(x-4)(x+1)\]So here we know that it will also equal zero when x is equal to 4, and when x is equal to -1.