Question

I just have a quick question! Will give medal!

Answer 1

You can't divide by zero right? It's undefined and in terms of a graph it becomes a vertical asymptote so you could say x is restricted when your denominator is 0, right?...

Answer 2

well if x-6=0, x=6... So what happens when we actually plug that in to our function? y=(6-4)/(6-6)=2/0. so the value of y(6) is undefined. Meaning x is restricted by that value. It can be any other real number, just not 6.

Answer 3

well if we plug in -6... y(-6)=(-6-4)/(-6-6)=-2/-12=1/6, which is a real value. Not restricted where t=-6. Only restriction is t=-6

Answer 4

New question and tag me. :)