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Mathematics 20 Online
OpenStudy (anonymous):

simplified form of 3x-6/x-z

OpenStudy (phi):

is that x-z or x-2 ?

OpenStudy (anonymous):

sorry x-2

OpenStudy (phi):

do you know how to factor 3 out of 3x-6 ?

OpenStudy (anonymous):

this is what i got (x-2) (x+3)/(x-2) i guess i factored it out

OpenStudy (phi):

factoring does not change the value. if you undo the factoring by multiplying you should get back what you started with. here is an example 2x +4 which is the same as 2*x + 2*2 notice that there is a 2* in both terms. we can factor this to be 2(x+4) for your problem 3x+6 this is the same as 3*x + 3*2 can you factor it ?

OpenStudy (anonymous):

no yes you can

OpenStudy (phi):

for your problem 3x+6 this is the same as 3*x + 3*2 what number is in both terms ?

OpenStudy (anonymous):

3

OpenStudy (phi):

yes, 3. you can "factor out 3". that means take the 3 out of each term and put the 3 in front of the parens: 3x - 3*2 becomes 3*(x -2) your expression is now \[ \frac{3(x-2)}{x-2}\] though it is complicated (x-2) divided by (x-2) is 1 anything (no matter how complicated it looks) divided by itself is 1 what do you get ?

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