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if f(x)=(2x+8)/(3x+8) find: f^-1(-1) f^-1(2)
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Let f(x) = y. In inverse function, x and y are switched to each other. Like this. f\(^{-1}\)(x) = x = (2y+8)/(3y+8) Now isolate y then plug -1 or 2 (depends on which problem you are working on) into x. Is this clear?
i tried that but i kept getting the wrong answer maybe i was calculating it wrong
oo i see what i did wrong i did 2(y+8)/3(y+8)
Oh, there you go, lol.
What did you get for f\(^{-1}\)(-1)?
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6/5?
it still says its wrong?
\[f^{-1}(x) = y = \dfrac{8x - 8}{2 - 3x}\]Is this what you get? No?
how did you get that?
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