12. How would you determine which way to shade the graph of 2x – 3y > 12? (2 points)
Easy. Pick a point where the arithmetic is easy. (0,0) is a classic. Is 2(0)-3(0) > 12 If it is, then (0,0) is in the shaded region. Otherwise, shade the other side of the line.
Okay, So the answer i should put is ( You determine it by picking a point where the arithmetic is easier?
You determine it by testing a point. If you're going to have to do the arithmetic, you might as well pick a point where the arithmetic is convenient, right?
Now if you have a series of inequalities, then you might be more constrained in your choice of test points, but usually if you graph the line of the inequality, you can spot a point to test that isn't too difficult to evaluate.
Does that make sense?
lol sorta, But i dont know what id put as the final answer
Test a point. If it satisfies the inequality, the test point is in the region to be shaded. Otherwise, the other side should be shaded.
Otherwise, the region not containing the test point should be shaded.
Ok im not gonna copy and paste that but so here = You determine it by testing a point and if it satisfies the inwquality, the test point that is within the region is to be shaded. but on the otherhand, The region not containing the test point should be shaded. ? is that good
I would make it clearer than "but on the other hand" — how about "if it doesn't satisfy the inequality, the region not containing the test point should be shaded"?
You determine it by testing a point and if it satisfies the inwquality, the test point that is within the region is to be shaded. but if it doesn't satisfy the inequality, the region not containing the test point should be shaded" is that better?
Yeah, that sounds fine.
Thank you so much
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