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Trigonometry
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Show that the equation 2tan^2 theta cos theta= 3 can be written in the form 2cos^2 theta + 3 cos theta=0
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\[\tan \theta = \frac{ \sin \theta }{ \cos \theta }\]Use substitution I think you have an error in your problem. I end up with \[2\cos ^{2}\theta+3\cos \theta = 2\]
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